电解硝酸银溶液反应式的化学方程式是什么?


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展开全部阳极反应:4OH- +4e- ==2H2O+O2(气体)
总反应:4AgNO3 + 2H2O == 4HNO3 + 4Ag(沉淀) + O2(气体) 补充: 阴极生成单质银,阳极生成氧气。因为银离子比氢离子得电子能力强,氢氧根离子比硝酸根离子失电子能力强。 追问: 其实总反应怎么写出来的?谢谢了 回答: 电解硝酸银,硝酸银是强电解质,存在硝酸根和银离子,银离子反应后溶液里就剩下大量的硝酸根离子,而阳极反应式消耗了水中的氢氧根离子,存在大量的氢离子,和硝酸根离子组合成硝酸,因为反应式消耗了4摩尔氢氧根,意思是消耗了4摩尔水,而最后阳极反应又生成了两摩尔水所以约掉两摩尔,反应物有两摩尔水,后面的银和氧气照写,是生成物,了解了吗?
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在阳极产生氧气的同时产生氢离子,那么阳极的硝酸根离子在酸性条件下氧化性变强,会不会强于氢离子而得电子的是硝酸根呢?...
在阳极产生氧气的同时产生氢离子,那么阳极的硝酸根离子在酸性条件下氧化性变强,会不会强于氢离子而得电子的是硝酸根呢?
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展开全部电解AgNO3溶液时的电极方程式为:阳极:4OH--4e-=O2↑+2H2O,注意此处的OH-是由水电离产生的,4OH-需要4H2O提供,由于H2O=(可逆号)H++OH-,因此当水提供的4OH-反应掉,则溶液中会相应产生4H+。所以这个电极方程式也可以改写成:4H2O-4e-=O2↑+2H2O+4H+,即:2H2O-4e-=O2↑+4H+阴极:4Ag+4e-=4Ag注意当电极反应根据电子得失守恒改写成总反应时,由于OH-由水电离产生,在总方程式中必须将OH-改写成H2O,因为H2O是弱电解质,这样得到的结果,实际是水参加了反应。已赞过已踩过你对这个回答的评价是?评论
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